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• bluejay188 (28)in #steemstem • 8 years ago

  RE: #Chemistry Challenge 5

  Don't you need to use it to account for the molar ratios of the balanced equation?

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• bluejay188 (28)in #steemstem • 8 years ago

  RE: #Chemistry Challenge 5

  Ah, that's how many Liters are required for 100 km, yet we're going 608 km. SO instead, 200 should be divided by 30.4 making the answer 1.50 x 10^-4 mol∙l^-1∙s^-1

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• bluejay188 (28)in #steemstem • 8 years ago

  RE: #Chemistry Challenge 5

  9.11 x 10^-4 mol∙l^-1∙s^-1 Ok, I think I've figured it out. So the Rate equation for this would be Rate = ((1/2)(d[C8H18]/dt)). You can find d[C8H18] by dimensional analysis…

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• bluejay188 (28)in #steemstem • 8 years ago

  RE: #Chemistry Challenge 5

  1.) 2 C8H18 + 25 O2 ===> 16 CO2 + 18 H2O 2.) 608 km (Dimensional Analysis) 3.) 70.3 kg CO2 3.9 x 10^4 L CO2 (Dimensional Analysis / Ideal Gas Law) 4.) .306 [C8H18]/hr (dc/dt)

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• bluejay188 (28)in #art • 8 years ago

  RE: | KatiepelC | Paramore - Hard Times (my live cover for steemit:)

  That was awesome, upvoted!

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• bluejay188 (28)in #music • 8 years ago

  RE: Hey everyone - Piano / I take requests!

  Thanks!

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• bluejay188 (28)in #music • 8 years ago

  RE: Hey everyone - Piano / I take requests!

  Thanks, and awesome - will do!

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