In this video I continue further in the Discovery Project series which I started in my last video. In this video I use the derivation of the area of a region below a curve but above a slanted line, which I solved in my last video, to solve for an area with a known function and slanted line. In this video I solve for the area of the region bounded by the curve y = x + sin(x) and the slanted line y = x - 2. This is a useful example on using the formula for the area so make sure to watch it and stay tuned for more on this Discovery Project series!
Download the notes in my video: https://onedrive.live.com/redir?resid=88862EF47BCAF6CD!104333&authkey=!AFHtmB2n9oYR2rM&ithint=file%2cpdf
View Video Notes on Steemit: https://steemit.com/mathematics/@mes/applications-of-integrals-discovery-project-rotating-on-a-slant-question-2
Related Videos:
Discovery Project: Rotating on a Slant: Question 1:
Discovery Project: Patterns in Integrals: Question 1: 1/((x+a)(x+b)):
Discovery Project: Patterns in Integrals: Question 2: sin(ax)cos(bx):
Discovery Project: Patterns in Integrals: Question 3: x^n * ln(x):
Discovery Project: Patterns in Integrals: Question 4: x^n * e^6:
Area Under a Curve: Introduction to Integral Calculus:
Derivative of Trigonometry Functions: Derivative of sin(x):
Derivative of Trigonometry Functions: Derivative of cos(x):
Properties of Definite Integrals - Part 1:
Properties of Definite Integrals - Part 2:
Trigonometry: Sine, Cosine and Tan Functions: .
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I don't always determine the area between a curve and a slanted line but when I usually use the area derivation I covered in my last video ;)
View Video Notes on Steemit: https://steemit.com/mathematics/@mes/applications-of-integrals-discovery-project-rotating-on-a-slant-question-2