Be the First to Solve this Math Test and Win an 100% upvote worth $0.7 Instantly #1

in #giveaway6 years ago (edited)

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Okay. Let's get started. The first person to solve the word problem below will get an upvote worth $0.7. There will also be some consolation upvotes for some of the late comers.

How To Participate:

Kindly UPVOTE this post and then answer the question which follows in the comment section. Entries that do not comply with this simple rule will be disregarded.

Question:

The minute hand of a wall clock is 14cm long. Given that the time is 11am, calculate the distance travelled by the minute hand when the time is exactly 11:15 am.

Deadline:

The test comes to an end once a winner emerges or at the expiration of this post. Good luck guys.

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Well I would use the formula C=(1/4)pidiameter to get the distance traveled by the minute hand.

So it would look like C=(1/4)pi28

This would make the answer 7*pi or about 21.991 cm

HELLO
ACCORDING TO MY MEASUREMENTS AND CALCULATIONS THE ANSWER SHOULD BE 20 CENTIMETERS.

Very close, but could be a bit better :) how did you do it?

did you say the minute hand has 14 cm. long

so i place the clock at 11:00 then i rotate the minute hand thru 11:15 and i took measurement from one point to another and my result was 20 cm.

so if a was wrong i hope someone can do it better.

thanks

ah I see it was close so i got curious :) it should be 22 if calculated!

Thanks!

X=3

It is the question in text below, how long the minute marker moves in CM during 15 min, if the minute marker it self is 14 cm.

13 centimeters?

Not quiet :) take another guess!

Will someone get the correct answer? :O

Hahaha I hope someone does.

The answer is 21.98cm...which is approximately 22cm

The minute hand serve has a radius. It moves 11am to 11:15 which is 90degrees. Using radian×radius. A radian is 180degrees which is equivalent to a pie(3.14). But here it moved 90degrees, which is 3.14/2=1.57..so the distance covered is 1.57×14=21.98

Nice, you get second place, a bit late :)

Answer is 44cm

Actually, it depends on how you define the "distance traveled" I would argue the distance traveled by the minute handle is 90° or pi/2 rad.

The distance traveled by the tip of the minute handle is pi/2 times 14 cm, i. e. (as stated before) 7pi or about 21.991 cm.

Equally unambiguous would be the area swept by the minute handle (assuming it doesn't have a tail). Which would be equal to pi times 14 squared divided by 4, or 49 pi being about 153.938 square cm.