No, as sum(n) = N; usually we use n to count things, here I've used it (not a great choice) as a value of one utxo.
I'm not sure this contradicts my original point, as the formula for B still only contains N, M, and t.
To have a chance to stake 64 times (within 16h) you would have to split N = 10 into 64 chunks of n=0.15625 each (equal ns for simplicity).
This is what I'm trying to get at, that the maximum number of blocks a person can stake is equal to the number of UTXOs that person has. Theoretically, if one makes more UTXOs than there are blocks in some time period, then a person could theoretically stake all of those blocks, though the probability of that will be extremely low.