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RE: LeoThread 2025-03-10 23:28

in LeoFinance7 months ago

Part 2/5:

To understand how to differentiate logarithmic functions, it is crucial to grasp what logarithms represent. A logarithm ( \log_a(x) ) answers the question: "To what exponent must the base ( a ) be raised to produce ( x )?" This can be expressed as ( a^y = x ), which rearranges to give ( y = \log_a(x) ).

Using implicit differentiation, we can find the derivative of ( y ) with respect to ( x ). By applying the rules of implicit differentiation to the equation ( a^y = x ), we can derive a formula for ( \frac{dy}{dx} ).

Derivative of ( \log_a(x) )

Let's start deriving the derivative of ( \log_a(x) ).

Starting with the equation ( a^y = x ), we take the derivative with respect to ( x ):

[

\frac{d}{dx}(a^y) = \frac{d}{dx}(x)

]

Using the chain rule, we acquire: