Part 3/6:
Next, we estimate how many times 1231 fits into 1381. It fits only once, so we write 1 above the division bar. We then multiply 1 by 1231, resulting in 1231. By subtracting this from 1381, we find the remainder, which is 150.
Continuing the Division Process
To proceed further, we bring down a zero next to the remainder, making it 1500. Again, we look at how many times 1231 goes into 1500, which is also once. We repeat the multiplication and subtraction process:
Multiply: ( 1 \times 1231 = 1231 )
Subtract: ( 1500 - 1231 = 269 )
We now repeat this process by bringing down another zero (making it 2690), asking how many times 1231 can fit into 2690, which it does twice. We follow through by multiplying and subtracting once more:
- Multiply: ( 2 \times 1231 = 2462 )