RE: LeoThread 2025-11-26 03-47

[ultimatestats]

With 23 people in a room, there's a 50% chance that two of them share the same birthday

Comments

[milaan]

The probability that at least two share a birthday=1 −P(everyone has a unique birthday)P(all unique)=365/365×364/365×363/365 ×..×(365 − 22)/365
(for 23 people, we check the 2nd through 23rd person)This works out to 0.4927
So 1−0.4927=0.5073

[ultimatestats]

yeah that's the classic way to calculate it - wild how it flips over 50% at just 23 people