Here’s a curious way to split a product of two integers into two summands:
For example, for n=3 and b=10,
Now since we can consider
where the n cancels out on the right hand side, we have the following
Take care
@qed
Here’s a curious way to split a product of two integers into two summands:
For example, for n=3 and b=10,
Now since we can consider
where the n cancels out on the right hand side, we have the following
Take care
@qed
I believe you but I still want the proof of that formula :3
The standalone b's cancel in (n - 1) · b + (b - n) and that's that.
ah right, nb-b+b-n is the same as nb-n. Didn't see that, thanks