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RE: RE: Why do complex zeros come in complex conjugate pairs? /

in #math8 years ago

Hey mate,

I think it would be nice to add some steps from "52 + 3 (a+b i) - (a+b i)^3" to "(-52 + a (3 + 3 b^2 - a^2)) + b (3 - 3 a^2 + b^2) i".

I forgot for a moment that (a+b i)^3 is a binomic formula, but I would still need pen&paper to check this step.

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Mate, before asking, just try it. That's the way to learn.
Take (x+y)^3 and expand it.
(x+y)^3
= (x+y)·(x+y)·(x+y)
= x·(x+y)·(x+y) + y·(x+y)·(x+y)
= ...
Do the work first.

mate, I am just trying to give you a hint. I never said that it is an impossible to understand step, but it would be easier to understand if you add more steps.

Do the work first.

No. I know how complex numbers and polynoms work. There is no need for me to calculate some arbitrary equations you came up with :P

Yes, mate.

Mate, ... :D