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RE: Brainsteem Mathematics Challenges: Factorial Sum

in #mathematics6 years ago

The positive integer are 2,3,5 and 7 and this has a common difference of 2 without considering the first term which the the only number given in the equation above.

Here is the solution.
Where a = 2 , b = 3 and c = 5
a! + b! + c! = (21)+(321)+(5432*1)
a! + b! + c! = (2) + (6) + (120)
a! + b! + c! = 128

From equation 2^n = 128 where 128 can be converted to power of 2 which is 2^7

Therefore n = 7, a = 2, b = 3 and c = 5

Thanks for this brainstorming.