E^x=(1+i)
Ln(e^x)=ln(1+i)
x=ln(1+i)
====
This is as far as I got by myself
Google says ln(1+i) = 0.34657359+0.785398163i
E^x=(1+i)
Ln(e^x)=ln(1+i)
x=ln(1+i)
====
This is as far as I got by myself
Google says ln(1+i) = 0.34657359+0.785398163i
Actually I want you try to find the log of complex numbers yourself.
It isn't that hard when you keep euler's formula in mind:
e^x+iy = e^x *(cos(y)+i*sin(y))