RE: LeoThread 2025-07-13 05:19

[ben.haase]

#python #iterating w/ optional breaker index #code #coding #snipped

Comments

[ben.haase]

Option A:

breaker_index = 5
for i, item in enumerate(items):
    if breaker_index is not None and i >= breaker_index:
        break

[ben.haase]

Option B:

for item in items[:breaker_index]:
    #Nothing to add here